Sending and receiving "File" over a socket

Babulesnik · 10-12-2011 11:57 AM

Really need to send or receive "File" in the socket. Since it is implemented in the "Connection"

PHP Code:

Bool dataFull (File & f, Int size, Bool send = true); 

**Esenthel** · 10-12-2011 12:34 PM

you can do it manually, using Memc<Byte>, File::put, get

I recommend that you use Connection (TCP/IP) or FastConnection (UDP) which have File based methods

Babulesnik · 10-12-2011 12:44 PM

Thanks I will try to use "FastConnection" . I have long been using "Connection" to connections of the client / server. But I need to transfer data between the clients client/client. I do it for unloading the server and wanted to implement it through sockets.

Babulesnik · 10-13-2011 08:46 PM

FastConnection only takes a sequence of values of type "Byte"

Code:

Int receive(SockAddr &addr, Byte (&data)[65536]);

How to do it would take "Str" and "Byte or Int" simultaneously ?.How it is implemented in "Connection".

**Esenthel** · 10-13-2011 09:05 PM

File::readMem, look into headers more carefully

Babulesnik · 10-13-2011 10:06 PM

(10-13-2011 09:05 PM)Esenthel Wrote: File::readMem, look into headers more carefully

Thank you. It's bad for me -> "order of received data is not guaranteed to be the same as when sending". How to use the Connection at the same time to communicate with the server and exchange between clients?

I use the "Connection" to connect a client / server - it works perfectly !.But how can I use this class to be used between clients if it is set once Bool clientConnectToServer(C SockAddr &server_addr); ?

I need some frequently transmit the position of some items, status of players in the "playroom" and other not very important data. I do not want to send them through the server to other players. I want to exchange the data between clients. It will not load the server. For example: WorldOfTanks on a single server supports 200 000 (200k!) players online

Babulesnik · 10-14-2011 05:23 PM

Who knows how this can be done?

Sadahar · 10-16-2011 01:35 PM

Over TCP/IP (Connection) the received data order IS guaranteed.
Just put that byte array you received into a File object

Code:

File filebuffer; // SIZE is 1024.

filebuffer.writeMem();

Byte buffer[1024];

Int count = socket.receive(buffer, SIZE(buffer));

for (int i = 0; i < count; i++)    filebuffer << buffer[i];

And there you have your data in the file as you received it.
Im not sure if that code works, I just arranged a little piece of mine's... Im not using Connection, but Socket, with a custom NetMgr class...

Also in TCP consider that if you send 2 pkts at the same time.. if they are small enought they will be merged into one.

Babulesnik · 10-16-2011 02:30 PM

(10-16-2011 01:35 PM)Sadahar Wrote: Over TCP/IP (Connection) the received data order IS guaranteed.
Just put that byte array you received into a File object

Code:

File filebuffer; // SIZE is 1024. filebuffer.writeMem(); Byte buffer[1024]; Int count = socket.receive(buffer, SIZE(buffer)); for (int i = 0; i < count; i++) filebuffer << buffer[i];

And there you have your data in the file as you received it.
Im not sure if that code works, I just arranged a little piece of mine's... Im not using Connection, but Socket, with a custom NetMgr class...

Also in TCP consider that if you send 2 pkts at the same time.. if they are small enought they will be merged into one.

Thank you very much.

Sending and receiving "File" over a socket
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