craksy
Member
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fade with LerpRS() question
ok i got a quesion about fading with the LerpRS() function.
i rewrote the Alpha() function from Blood massacre a little bit to make it easier to understand (for me at least), so now i have this:
Code:
/******************************************************************************/
#include "stdafx.h"
#include "Main.h"
/******************************************************************************/
Image img, img2;
/******************************************************************************/
static Flt Alpha(Flt IN_START, Flt IN_END, Flt OUT_START, Flt OUT_END)
{
Flt t = StateActive->time();
if(t <= IN_END){
return LerpRS(IN_START, IN_END, t);
}
else{
return LerpRS(OUT_END, OUT_START, t);
}
}
bool initIntro()
{
img = "logo2.gfx";
img2 = "craksyLogo.gfx";
return true;
}
bool updateIntro()
{
if(StateActive->time() >= 15)stateMenu.set(0.5);
return true;
}
void drawIntro()
{
D.clear(WHITE);
img.drawFs (ColorAlpha(Alpha(1,3,6,8)));
img2.drawFs(ColorAlpha(Alpha(8,10,10,0)));
}
/******************************************************************************/
State stateIntro(updateIntro, drawIntro, initIntro);
/******************************************************************************/
the problem is... i still don't have the slightest idea of how this works :S
i tried to take a look at the LerpRS() function, but i didn't really get it :/
it would be nice if one of you guys could explain it to me  and in a language i understand xD
Thanks in advance 
-Craksy
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| 10-10-2009 05:16 AM |
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Esenthel
Administrator
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Re: fade with LerpRS() question
LerpRS gets the "step" between two values (0..1)
have a range 0..100
if you use LerpRS(0,100, 0) you'll get 0.0
if you use LerpRS(0,100, 50) you'll get 0.5
if you use LerpRS(0,100, 100) you'll get 1.0
have a range 10..20
if you use LerpRS(10,20, 10) you'll get 0.0
if you use LerpRS(10,20, 15) you'll get 0.5
if you use LerpRS(10,20, 20) you'll get 1.0
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| 10-10-2009 01:50 PM |
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craksy
Member
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Re: fade with LerpRS() question
aah  c that made it alot easier to understand xD
thanks a lot
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| 10-10-2009 02:24 PM |
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