Calling visible() on a gui object returns true even when the gui object hasn't been created yet. Shouldn't a gui object's visibility be false until it is created?

Therefore checking if a gui object is visible requires doing this.


You should be able to do just this.

Why would you check if it is visible before it is created?

When you have a complex gui with windows that survive across states, sometimes a state doesn't know if a window has been created or not. All the state wants to know is if the window is visible or not.

I think that by default a window that has not been created yet should return false as visible, not true.

Why dont u just add yourself a bool to your custom gui window class? On creation set the window to hide and bool on false.. and on show vice versa.

it's safe to assume that when object is not yet created then it's not visible and not hidden (visibility is undefined), please use is() && visible() as in your codes

Still makes no sense to me though... how can a gui object be considered visible before it has even been created?? Oh well, I guess I can live with it.

Great to see this has been fixed in the latest update... just got to wait for a EE 1.0 update now.